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74 lines
2.5 KiB
Python
74 lines
2.5 KiB
Python
from sqlalchemy.orm import noload
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from sqlalchemy.sql._typing import ColumnExpressionArgument
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from typing import List, Dict, Any, Optional
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from iti.applications.extensions import db
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from iti.applications.models import SysMenu
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from iti.applications.common.enums import StatusEnum, MenuTypeEnum
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from iti.applications.common.utils import (
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build_tree_from_list,
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)
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from sqlalchemy import select
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def get_menu_tree(
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parent_id: Optional[str] = None,
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include_disabled: bool = True,
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type_filter: Optional[List[MenuTypeEnum]] = None,
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status_filter: Optional[List[StatusEnum]] = None,
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) -> List[Dict[str, Any]]:
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"""
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获取菜单树
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Args:
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parent_id: 父菜单ID 不填为所有树，若填写则只返回该父菜单的子菜单树(包括父菜单)
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include_disabled: 是否包含禁用菜单
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type_filter: 菜单类型过滤 不填为不限制
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status_filter: 状态过滤 不填为不限制
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"""
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# 获取所有菜单数据
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cte_query = build_descendants_cte(SysMenu.parent_id == parent_id)
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if not include_disabled:
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cte_query = cte_query.filter(SysMenu.status == StatusEnum.ENABLED)
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if type_filter:
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cte_query = cte_query.filter(SysMenu.type.in_(type_filter))
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if status_filter:
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cte_query = cte_query.filter(SysMenu.status.in_(status_filter))
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cte_query = cte_query.order_by(SysMenu.parent_id, SysMenu.sort).options(
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noload(SysMenu.parent), noload(SysMenu.children)
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)
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# 使用增强的树工具构建树结构
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return build_tree_from_list(db.session.scalars(cte_query).all())
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def build_descendants_cte(*criterion: ColumnExpressionArgument[bool]):
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"""
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构建获取后代的递归CTE
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"""
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hierarchy = (
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select(SysMenu.id, SysMenu.parent_id)
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.filter(*criterion)
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.cte("hierarchy", recursive=True)
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)
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bt = select(SysMenu.id, SysMenu.parent_id).join(
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hierarchy, hierarchy.c.id == SysMenu.parent_id
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)
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q = hierarchy.union_all(bt)
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return select(SysMenu).join(q, SysMenu.id == q.c.id)
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def build_ancestors_cte(*criterion: ColumnExpressionArgument[bool]):
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"""
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构建获取祖先的递归CTE
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"""
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hierarchy = (
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select(SysMenu.id, SysMenu.parent_id)
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.filter(*criterion)
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.cte("hierarchy", recursive=True)
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)
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bt = select(SysMenu.id, SysMenu.parent_id).join(
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hierarchy, hierarchy.c.parent_id == SysMenu.id
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)
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q = hierarchy.union_all(bt)
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return select(SysMenu).join(q, SysMenu.id == q.c.id)
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